Replying to @TaghiKhaje
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Replying to @TaghiKhaje
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Replying to @TaghiKhaje
x+y=2
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Replying to @TaghiKhaje
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Replying to @TaghiKhaje
Hi. Thanks for the puzzle. 2.000... using HASKELL. :)
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Replying to @TaghiKhaje
→ x, y > 0: ∛[(x³ + y³)/2] ≥ (x + y)/2 ⇒ 1 ≥ (x + y)/2 ⇒ 2 ≥ x + y, and equality holds when x = y = 2; → x ≤ 0 or y ≤ 0: proof of @Ahmed90327584 seems to be very very fine...! 🙂👍🏾👌🏾👏🏾👏🏾
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and equality holds when x = y = 1
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